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Get the date of last update of users's Password
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| Get the date of last update of users's Password.
If it is about a user, it's simply, the commandd is "chage -l user".
But it's trouble to input commands for a user if users are many.
So, the example below is the way of display all user's one at one time.
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| [1] | Example |
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[root@dlp ~]# cut -d: -f1 /etc/passwd | while read line; do echo -n $line; chage -l $line | head -1 | awk -F: '{print $2}'; done root Sep 12, 2009 bin Sep 12, 2009 daemon Sep 12, 2009 adm Sep 12, 2009 hiroyuki Sep 30, 2009 postfix Oct 17, 2009 |
| [2] | If OS is Solaris or othes that does not have a command 'chage it's impossible to get get them like above, so Change the code like below. All OK. |
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[root@dlp ~]# vi lastchange.sh
#!/bin/sh IFS=: today=`expr \`date +%s\` / 60 / 60 / 24` while read a b c d e f g h i; do if [ "$b" != '*' -a "$b" != '!!' ]; then last=`expr $today - $c` echo "$a = `date --date "-$last day" +%Y/%m/%d`" fi done < /etc/shadow [root@dlp ~]# chmod 700 lastchange.sh [root@rx7 ~]# ./lastchange.sh root = 2009/09/12 cent = 2009/09/14 hiroyuki = 2009/10/20 |